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1.4x^2+24x-144=0
a = 1.4; b = 24; c = -144;
Δ = b2-4ac
Δ = 242-4·1.4·(-144)
Δ = 1382.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-\sqrt{1382.4}}{2*1.4}=\frac{-24-\sqrt{1382.4}}{2.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+\sqrt{1382.4}}{2*1.4}=\frac{-24+\sqrt{1382.4}}{2.8} $
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